Question

Need help anyone know how to do this

Answer 1

∠ ECF = 32°

Explanation:

DE is the midsegment of Δ ABC and is therefore parallel to the third side BC.

Since DE and BC are parallel lines, then

∠ ECF and ∠ AED are congruent ( corresponding angles ) , thus

∠ ECF = ∠ AED = 32°

Answer 2

ΔABC has: AD=DB

AE = EC

=> DE is the median line of ΔABC

=> DE // BC

=> m∠AED = m∠ECF = 32°

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Explanation: