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The length of a rectangle is 2 ft longer than its width. If the perimeter of the rectangle is 40 ft, find its area.
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The length of a rectangle is 2 ft longer than its width.

If the perimeter of the rectangle is 40 ft, find its area.

User JohnFF
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2 Answers

2 votes
set the length=2 + w
and the width=w

P = 2l + 2w
40 = 2(2+w) + 2(w)
40 = 4 + 2w + 2w
36 = 4w
w = 9

therefore length=2+w=2+9=11
and width=w=9

Area = length x width
A = 11 x 9 = 99
User Adam McKee
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7.8k points
1 vote

Answer: yes

Explanation:

User Kelz
by
7.4k points
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