Question

5. Which of the following equations would

have no solutions?
A. 10x + 3 = 3 + 10x
B. -8 + 16x = 16x - 8
C. 4(2x - 3) = 8x - 12
D. 12 - 6x = -6x - 12

Answer 1

D

Explanation:

for A if you subtract 3 from both sides and divide by 10 from both you get x = 0 so that has infinate solutions

for B you add 8 to both sides and divide by 16 getting the same thiong as A

For C you ditribut 4 to 2x and -3 getting 8x-12=8x-12 if you solve it you get the answer as A & B

For D if you subtract 12 from one side you get -6x = -6x -12 (-12)

causing you not to be able to solve it