Question

The perimeter of a rectangle is 80 cm. The width is 10 cm more than twice the length. What

is the length and width of this rectangle? P=2W+2L

Answer 1

L=10cm , W=30cm

Explanation:

First use the given that W=10+2*L

Use P=2W+2L=80, substitute W in the perimeter formula

2(10+2L)+2L=80 and solve for L,

20+4L+2L=80 isolate variable L and combine like terms,

6L=80-20,

L=10, so W=10+2*10=10+20=30