Question

A child attempts to move a 90.01 kilogram refrigerator in order to retrieve a rubber

ball from behind it. If she is able to slide the refrigerator across the floor with 55
Newtons of force (ignoring friction), what would be its acceleration?

Answer 1

`a=0.611\ m/s^2`

Step-by-step explanation:

Given that,

Mass of a refrigerator, m = 90.01 kg

She is able to slide the refrigerator across the floor with 55 N of force.

We need to find the acceleration of the refrigerator.

Let it is a. Using second law of motion:

F = ma

`a=(F)/(m)\\\\a=(55\ N)/(90.01\ kg)\\\\a=0.611\ m/s^2`

So, its acceleration is
`0.611\ m/s^2`.