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For an acute angle θ,the equation sin(49) =cos(θ) is true. what is your value of θ?​

User Bens
by
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1 Answer

10 votes

Answer:


\theta = 41^(\circ)

Explanation:


~~~~~~~\sin 49^(\circ) = \cos \theta\\\\\implies \theta = \cos^(-1)\left(\sin 49^(\circ) \right)\\\\\implies \theta = \cos^(-1) \left[\cos \left(90^(\circ) - 49 ^(\circ) \right) \right]\\\\\implies \theta= \cos^(-1)\left( \cos 41^(\circ) \right)\\\\\implies \theta = 41^(\circ)

User Charnjeet Singh
by
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