Question

Each vertical cross-section of the triangular prism shown below is an isosceles triangle.What is the slant height, 8, of the triangular prism?

Answer 1

Answer: 5.4 units

Using Pythagoras Theorem:

a² + b² = c²

Here given following:

a = 2

b = 5

c = slant height

Solve for s:

s² = 2² + 5²

s² = 4 + 25

s² = 29

s = √29 = 5.38 ≈ 5.4 (rounded to nearest tenth)

Answer 2

Explanation:

Given: h(height) = 5

b(breadth) = 4

Therefore, Using Pythagoras theorem:

`(slant \: height)² = {h}^(2) + {b}^(2) \\ \: \: \: \: \: \: \: = {5}^(2) + {4}^(2) \\ \: \: \: = 25 + 16 \\ \: \: \: \: \: \: \: \: \: = (41)²`

= 1681

Hope it helps