Question

23) What is the equation of the line below?
24) What is the equation for the table below?

Answer 1

First of all, you need to find the slopes of each. To do this, we need to take 2 points from each and plug them into y2 -y1/ x2 - x1.

For the graph we will take the points given (0,5) (4,0)

0 - 5 / 4 -0 = -5/4 = your slope for the graph

For the table, we will take the first three points. (-1,-1) (0,3) (1,7)

7 - 3 / 1 - 0 = 4 / 1 = 4

3 - - 1 / 0 - - 1 = 4 / 1 = 4

Therefore, the slope of the table is 4.

Now, for the y-intercepts.

These are normal be the points (0, y)

For the graph this would be (0,5) and for the table it would be (0,3)

Slope - intercept form = y = mx + b, where m is the slope and b is the y-intercept form.

Soo,

For the graph, it would be;

Y = -5/4x + 5

And for the table, it would be;

Y = 4x + 3