Question

Help me answer asap please

Answer 1

see explanation

Explanation:

sinG =
`(opposite)/(hypotenuse)` =
`(HI)/(GI)` =
`(2)/(2√(2) )` =
`(1)/(√(2) )` =
`(√(2) )/(2)`

cosG =
`(adjacent)/(hypotenuse)` =
`(GH)/(GI)` =
`(2)/(2√(2) )` =
`\frac{1}{\sqrt{√(2) } }` =
`\frac{\sqrt{√(2) } }{2}`

tanG =
`(opposite)/(adjacent)` =
`(2)/(2)` = 1