Register
Ms. Miller was jogging at a constant rate of 6 miles per hour. After 3 hours, she was 15 miles away from her home. How far away from her home did she begin her jog? (Hint: you have a slope and a point.
147k views
1 vote
Ms. Miller was jogging at a constant rate of 6 miles per hour. After 3 hours, she was 15 miles away from her home. How far away from her home did she begin her jog? (Hint: you have a slope and a point. Plug them in to find her starting value).

User Daniel Pinyol
by
6.4k points

2 Answers

4 votes
18+15=33
she was 33 miles away from her home
User Drpelz
by
6.7k points
4 votes

Answer:

3 miles away from the house

Explanation:

6 * 3 =18

18 - 15=3

User Delirium
by
6.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.8m questions

10.5m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Write words to match the expression. 24- ( 6+3)
Link Copied!