Question

If a 750.0 gram sample of water is cooled for 95.0 oC to 17 oC, how much heat is released? CP = 4.18 J/g oC

Answer 1

Heat, Q = 262 kJ

Step-by-step explanation:

Given that,

Mass of a sample, m = 750 g

Initial temperature,
`T_i=95^0\ C`

Final temperature,
`T_f=17^0\ C`

The specific heat of the sample,
`c=4.18\ J/g^0 C`

We need to find the amount of heat released. The amount of heat released is given by the formula as follows :

`Q=mc\Delta T\\\\Q=750* 4.48* (17-95)\\\\Q=-262080\ J\\\\Q=-262\ kJ`

So, 262 kJ of heat is released by the sample.