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PLZ HURRY!!!

What is the equation of the line in slope-intercept form?

Line on a coordinate plane. The line runs through points begin ordered pair negative 5 comma 0 end ordered pair and begin ordered pair 0 comma 3 end ordered pair.

Enter your answer in the boxes.

y =
x +

User Aviv
by
6.1k points

2 Answers

4 votes

Answer:

y =
-(3)/(5) x + 3

Explanation:

To find slope you need to take y2-y1 divided by x2-x1. First to the subtraction. Y2 is 3 in this problem and y1 is 0. X2 is 0 and x1 is 5. 3-0 = 3 and 0-5 = -5. Now we have the equation
-(3)/(5) as the slope.

Slope-intercept form is y= mx+b so plug in
-(3)/(5) to get y =
-(3)/(5) x + b

The y-intercept is the coordinate where the x is equal to zero. (0,3) is the coordinate that meets this requirement. The y coordinate is 3 so that is the y-intercept. Plug that in to y =
-(3)/(5) x + b to get =
-(3)/(5) x + 3.

User Arlette
by
7.1k points
5 votes

The other person was parcially correct, but here is the right answer:

PLZ HURRY!!! What is the equation of the line in slope-intercept form? Line on a coordinate-example-1
User Mehdi Hosseini
by
6.6k points
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