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Find the equation of the line that contains the point (-1,-3) and is perpendicular to the line 3x-5y= 2

1 Answer

7 votes

Answer:

5x +3y = -14

Explanation:

The equation of the given line is in standard form. This makes it easy to write the equation for a perpendicular line.

__

form

The perpendicular line will have a slope that is the negative reciprocal of the slope of the given line. This can be made to happen by ...

  • swapping the coefficients of x- and y
  • negating one of the coefficients.

So, the line perpendicular to 3x -5y = 2 will have an equation of the form ...

5x +3y = c . . . . . for some constant c

constant

The constant will be what is needed to make the line go through the given point. That is, for (x, y) = (-1, -3), the equation is satisfied.

5(-1) +3(-3) = c = -5 -9 = -14 . . . . . substitute values for x and y

equation

Then the equation for the perpendicular line through (-1, -3) is ...

5x +3y = -14

Find the equation of the line that contains the point (-1,-3) and is perpendicular-example-1
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