Answer:
![\huge\boxed{\text{(B)}\ 0.41}](https://img.qammunity.org/2021/formulas/mathematics/high-school/x27x6th9rqfnu2ep37vywxlpw8olde6xtk.png)
Explanation:
This table will prove to be helpful to find the probability that a student has a cell phone and is from School B.
First off, we know that a total of 1000 students were interviewed, both from School A and from School B.
We also know that 479 of those 1000 were from School B (total on the right).
Looking further into School B, we can see that 408 students from school B have a cell phone.
Therefore, we can find the probability by finding 408 / 1000.
![408 / 1000 = 0.408 \approx 0.41](https://img.qammunity.org/2021/formulas/mathematics/high-school/m8t1709tf995v536e3qalpgqwpms1oe89g.png)
Therefore, the probability that a randomly selected student is from School B and has a phone is 0.41, or 41%.
Hope this helped!