Question

A pumpkin is thrown out of a window that is 4 feet high with an upward velocity of 14. When will the pumpkin hit

the ground?
A. 0.4 seconds
OB. 1.1 seconds
O c. 7 seconds
OD. 0.22 seconds

Answer 1

Explanation:

Given

Height H = 4 feet

Velocity = 14ft/s

Required

Time the pumpkin will hit the ground

Using the equation of mottion

H = ut + 1/2gt²

4 = 14t + 1/2(9.8)t²

4 = 14t + 4.9t²

4.9t²+14t-4 = 0

t = -14±√196+16(4.9)/2(4.9)

t = -14±√196+78.4/2(4.9)

t = -14±16.57/9.8

t = -14+16.57/9.8

t = 2.57/9.8

t = 0.2seconds