Question

Pythagorean theorem level two deltamath. help asap!!

Answer 1

Third side is 65

Explanation:

FORMULA

a^2 + b^2 = c^2

PLUG IT IN

33^2 + 56^2 = c^2

33 and 56 are the legs of the triangle so they go into the A and B variable.

The legs make up the right angle.

C is the hypotenuse, and here it is the diagonal line in that image.

FIND THE NUMBERS SQUARED

1089 + 3136 = c^2

ADD THEM TOGETHER

4225 = c^2

SQUARE ROOT BOTH SIDES

`√(4225)` = (
`√(C)`)^2

65 = c

CHECK

33^2 + 56^2=65^2

1089 + 3136 = 4225

4225 = 4225

Answer 2

65

Explanation:

Just use the Pythagorean theorem.

`\boxed{a^2+b^2=c^2}`

`33^2 + 56^2 = c^2\\1089 + 3136 = c^2\\4225 = c^2\\c = √(4225) \\c= 65`