Question

Jude has 30 coins of quarters and nickels. The total amount he has is $5.10. How many of each coin does Jude have? Write the system. Write the equations in the order that they appear in the problem.

Answer 1

Answer: Required system

x+y= 30

0.25x+0.05y=5.10

Jude has 18 quarters and 12 nickels.

Explanation:

Let x= Number of quarters

y= Number of nickels

As per given,

x+y= 30 (i)

0.25x+0.05y=5.10 (ii) [1 quarter = $0.25 , 1 nickel = $0.05]

Multiply 0.25 on both sides of equation (i)

0.25x+0.25y= 7.5 (iii)

Eliminate (ii) from (iii) , we get

0.20y=2.4

⇒ y = 12 [divide both sides by 0.20]

Put value of y in (i\), we get

x+12=30

⇒ x= 30-12= 18

Hence, Jude has 18 quarters and 12 nickels.