Question

Approximately what mass of CuSO4*5H20 (250 g mol^-1) is required to prepare 250 mL of 0.10 M copper(ll)

sulfate solution?
A) 4.0 g
B
6.2 g
С
34 g
D
85 g
E
140 g

Answer 1

Mass of CuSO₄.5H₂0 = 6.25 g (B)

Further explanation

MW CuSO₄.5H₂0 =250 g/ mol

mol of CuSO₄

`\tt 0.25* 0.1=0.025`

mass of CuSO₄ (MW=159.61 g/mol)

`\tt 0.025* 159.61=3.99~g`

`\tt mass~CuSO_4=(159.61)/(250)* mass~CuSO_4.5H_2O\\\\mass~CuSO_4.5H_2O=(3.99* 250)/(159.61)=6.25~g`