Question

H(-4)=x^2-8x please solve

Answer 1

Putting h=-4 in the function
`h(x)=x^2-8x` we get
`\mathbf{h(-4)=48}`

Explanation:

We are given:
`h(x)=x^2-8x`

We need to find h(-4)

Put x= -4 and solve:

`h(x)=x^2-8x\\Put \ x=-4\\h(-4)=(-4)^2-8(-4)\\h(-4)=16+32\\h(-4)=48`

So, putting h=-4 in the function
`h(x)=x^2-8x` we get
`\mathbf{h(-4)=48}`