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Evaluate x+y when x=−4\5 and y=1\3. Write your answer as a fraction or mixed number in simplest form.

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Answer:

When x=−4\5 and y=1\3 we get x+y = -7/15

Explanation:

We are given :

x=−4\5 and y=1\3

We need to evaluate : x+y

Solving:


x+y\\=-(4)/(5)+(1)/(3)

Taking LCM of denominators 5 and 3, we get 15


=(-4*3+1*5)/(15)\\=(-12+5)/(15)\\=(-7)/(15)

So, when x=−4\5 and y=1\3 we get x+y = -7/15

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