Simplify ^3 sq try (-0.05)^24

Question

asked Aug 2, 2021 186k views

2 Answers

Burakozgul · Answer 1 · 2021-08-06T23:00:16+0000

Answer:

As

so option D is correct.

Explanation:

Given the expression

$\sqrt[3]{\left(-0.05\right)^(24)}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{(1)/(n)}$

$\sqrt[3]{\left(-0.05\right)^(24)}=\left(\left(-0.05\right)^(24)\right)^{(1)/(3)}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^(bc)$

$=\left(-0.05\right)^{24\cdot (1)/(3)}$

$=\left(-0.05\right)^8$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

=0.05^8

Hence, the simplification will be:

$\sqrt[3]{\left(-0.05\right)^(24)}=0.05^8$

Therefore, option D is correct.