Question

Hi Jose, when you submit this form, the owner will be able to see your name and email address.

1. A 100. g samle of water absorbs how many Joules of energy as its temperature is changed from
35.0 C to 60.0 C. (water s = 4.184 J/g C)

Answer 1

10460J

Step-by-step explanation:

Given parameters:

Mass of water sample = 100g

Initial temperature = 35°C

Final temperature = 60°C

Unknown:

Amount of energy absorbed by water = ?

Solution:

The amount of energy absorbed by water is mathematically expressed below;

H = m C ΔT

H is the amount of energy

m is the mass

C is the specific heat capacity of water = 4.184J/g°C

ΔT = 60°C - 35°C = 25°C

Now insert the parameters and solve;

H = 100 x 4.184 x 25 = 10460J