Question

What mass of water can be heated from 10.0 C to 38.0 Celsius by addition of 3,500j? (Specific heat capacity of water is 4.18 j/g C)

Answer 1

Mass of water : 29.904 g

Further explanation

Heat can be formulated

Q=m.c.Δt

Q, heat, J

m,mass, g

c, specific heat, j/g C

Δt,temperature, C

• Δt,temperature

`\tt 38-10=28^oC`

• mass of water

`\tt m=(Q)/(c.\Delta t)\\\\m=(3500)/(4.18* 28)\\\\m=29.904~g`