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Two hot air balloons are flying above a park. One balloon started at a height of 3,000 feet above the ground and is decreasing in height at a rate

of 40 feet per minute. The second balloon is rising at a rate of 50 feet per minute after beginning from a height of 1,200 feet above the ground.

Given that h is the height of the balloons after m minutes, determine which system of equations represents this situation.
A. h=3,000-40m
h=1,200+50m

B. h=3,000+40m
h=1,200-50m

C. h=3,000m-40
h=1,200m+50

D. m=3,000-40h
m=1,200+50h​

User Gented
by
8.3k points

2 Answers

3 votes

Answer:

the answer is A

Explanation:

you said that the first balloon was falling at a rate of 40 feet per minute.that would be 3,000-40m. then you said the second balloon was rising at a rate of 50 feet per minute. that would be 1,200+50m. ther is your answer

User Travis Christian
by
8.7k points
4 votes

Answer:

  • A. h=3,000-40m
  • h=1,200+50m

Explanation:

Height of the first balloon:

  • h = 3000 - 40m

Height of the second balloon:

  • h = 1200 + 50m

Correct option is A.

User Eliavs
by
8.4k points

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