Question

What is the equation of the line through (2, –1) and (0, 5)?

Answer 1

(y-y1)=m(x-x1)

y+1=5+1/0-2(x-2)

y+1=6/-2(x-2)

-2y-2=6x-12

6x+2y+14=0

Answer 2

B

Step-by-step explanation:

To find the equation, we can use the point-slope form:

Where m is the slope and (x₁, y₁) is a point.

First, we will need to find the slope. Since we have two points, we can use the slope formula:

Let (2, -1) be (x₁, y₁) and let (0, 5) be (x₂, y₂). Substitute appropriately and evaluate:

Therefore, the slope m is -3.

Now, we can use the point-slope form. We also need a point. Let’s use (2, -1) for consistency. So, we will substitute -3 for m and (2, -1) for (x₁, y₁). This yields:

We will now convert this to slope-intercept form. Simplify the left and distribute the right:

Subtract 1 from both sides. Therefore, our equation is:

Thus, our answer is B.