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In the diagram, ABCD is a parallelogram. The

diagonals of the parallelogram intersect at point T.
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In the diagram, ABCD is a parallelogram. The diagonals of the parallelogram intersect-example-1
User Starlett
by
8.3k points

1 Answer

1 vote

Answer:

A. 100 degrees

Explanation:

Given:


m\angle ABC = 3y + 5


m\angle ADC = 5y - 45

Required:


m\angle BCD

SOLUTION:

✍️First, create an equation that you will use to find the value of y.


m\angle ABC = m\angle ADC (opposite angles of a parallelogram are congruent to each other)


3y + 5 = 5y - 45 (substitution)

Collect like terms


3y - 5y = -5 - 45


-2y = -50

Divide both sides by -2


y = 25

✍️Next, find
m\angle ABC and
m\angle ADC.


m\angle ABC = 3y + 5

Plug in the value of y


m\angle ABC = 3(25) + 5 = 75 + 5 = 80


m\angle ADC = 5y - 45

Plug in the value of y


m\angle ADC = 5(25) - 45 = 125 - 45 = 80

✍️Next, find
m\angle BCD.


m\angle BCD + m\angle ADC = 180 (consecutive angles in a parallelogram are supplementary)


m\angle BCD + 80 = 180 (substitution)

Subtract 80 from each side


m\angle BCD = 180 - 80


m\angle BCD = 100

User Jaecheol Park
by
7.8k points

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