Question

The specific heat of a substance is 0.38 J/goC. How much energy is required to raise the temperature of 42 g of the substance from 25oC to 39oC?

Answer 1

223.4J

Step-by-step explanation:

Given parameters:

Specific heat capacity of substance = 0.38J/g°C

Mass of substance = 42g

Initial temperature = 25°C

Final temperature = 39°C

Unknown:

Energy required to raise the temperature = ?

Solution:

The amount of heat required by the substances can be derived using the expression below;

H = m c Δt

H is the amount of heat energy

m is the mass

c is the specific heat capacity

Δt is the change in temperature;

Δt = 39°C - 25°C = 14°C

Now insert the parameters and solve;

H = 42 x 0.38 x 14 = 223.4J