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what is the amount of heat energy released when 50.0 grams of water is cooled from 20.0 degrees Celcius

1 Answer

4 votes

Answer:

q = mC∆T

q = (50 g)(4.184 J/g/deg)(10 deg)

q = 2092 J = 2.09x10^3 J

That's how it's done.

Step-by-step explanation:

Hope this helps! sorry If i didn't simplify enough..

User Upalr
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