Question

2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation is given below: Nal (s) + Cl, (g) → NaCl (s) + 1, (g)​

Answer 1

0.88g

Step-by-step explanation:

The reaction equation:

2NaI + Cl₂ → 2NaCl + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

Number of moles =
`(mass)/(molar mass)`

Molar mass of NaI = 23 + 126.9 = 149.9g/mol

Now insert the parameters and solve;

Number of moles =
`(2.29)/(149.9)` = 0.015mol

So;

From the balanced reaction equation;

2 moles of NaI produced 2 moles of NaCl

0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

Mass = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Now;

Mass of NaCl = 0.015 x 58.5 = 0.88g