Question

Factorise fully 2x^2-8x

Answer 1

2x(x-4)

Explanation:

2
`x^(2)`-8x= 2(
`x^(2)`-4x)= 2x(x-4)

Answer 2

`\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)`

Explanation:

Given the expression

`2x^2-8x`

`\mathrm{Apply\:exponent\:rule}:\quad \:a^(b+c)=a^ba^c`

`x^2=xx`

so the expression becomes

`2x^2-8x=2xx-8x`

`=2xx-2\cdot \:4x`

`=2x\left(x-4\right)` ∵
`\mathrm{Factor\:out\:common\:term\:}2x`

Therefore,

`\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)`