Answer:
f(x) = 0 on x= -1 and x = -2
Explanation:
Given function is:

In order to find the value of x on which the function will have value zero we have to factorize the function and find zeroes of the function. The method used will be factorization of polynomial as the function is in polynomial form.
So,

To find the zeroes, putting the function = 0

Hence,
f(x) = 0 on x= -1 and x = -2