Question

A cylindrical-shaped hole is 42 feet deep and has a diameter of 5 feet.

Approximately how large is the hole?

Answer 1

C. 825 ft³

Explanation:

Height of the hole = 42 ft

Radius of the hole = ½*diameter = ½*5 = 2.5 ft

How large the hole is = the volume of the cylindrical hole

Volume =
`\pi r^2h`

Plug in the values

`Volume = \pi *2.5^2*42 = 824.67`

The hole is approximately 825 ft³ large (nearest whole number).