158k views
4 votes
Z+w−3=k
6z−10w=8






User Jlabedo
by
8.9k points

2 Answers

3 votes

Answer:

Explanation:

Please, include the instructions.

I'm assuming you want to solve this system of linear equations for z and w, assuming that k is an unknown constant.

Use the method of elimination by addition and subtraction. To eiiminate w, multiply all four terms of the first equation by 10, obtaining:

10 z + 10w - 30 = 10k

6z - 10 w = 80

Then 16z - 30 - 80 = 10k, or

16z -110 = 10k, Simplifying this, we get:

10(k + 11)

z = ---------------

16

Substituting this expression for z into the first equation, we get:

(10/16)(k + 11) + w - 3 = k. We must solve this for w:

-(10/16)(k + 11) + w - 3 = k), or

-(10/16)(k + 11) - w + 3 = -k

Then -(10/16)(k + 11) + 3 + k = w

and so the solution, in terms of the unknown constant k, is

10(k + 11)

( --------------, -(10/16)(k + 11) + 3 + k )

16

User Taro Sato
by
7.9k points
3 votes

Answer:

if your looking for z it is 5/8k+2.375

Explanation:

User Dfan
by
8.3k points

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