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Under certain conditions, the number of bacteria present in a colony is approximated by f(t) = Age 0.023t, where t is in minutes. If A = 2,700,000, find the number of bacteria present at 5 minutes, 10 minutes, and 60 minutes.

User KeyboardP
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1 Answer

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Answer:

  • 5 min: 3,029,058
  • 10 min: 3,398,220
  • 60 min: 10,732,234

Explanation:

The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).

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5 minutes

The number of bacteria present after 5 minutes is about ...

f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058

10 minutes

The number of bacteria present after 10 minutes is about ...

f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220

60 minutes

The number of bacteria present after 60 minutes is about ...

f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234

Under certain conditions, the number of bacteria present in a colony is approximated-example-1
User Jitendra Tiwari
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