What is the solution to the equation below? Log7 + log(x-4) = 1

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asked Sep 2, 2023 170k views

25 votes

What is the solution to the equation below? Log7 + log(x-4) = 1

Mathematics
high-school

Gerhard Brueckl asked

by Gerhard Brueckl

7.2k points

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2 Answers

7 votes

Answer:

38/7

Explanation:

Moinudin answered Sep 3, 2023

by Moinudin

7.6k points

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6 votes

Answer:

$x= \frac{38}7$

Step by step explanation:

$~~~~~~~\log_(10) 7 + \log_(10)(x-4) = 1\\\\\implies \log_(10)(7(x-4)) = \log_(10) 10~~~~~~~~~~~~~~~;[\log_b(mn) = \log_b m + \log_b n]\\\\\implies 7(x-4) = 10\\\\\implies 7x -28 = 10\\\\\implies 7x = 10 +28 \\\\\implies 7x = 38\\\\\implies x= \frac{38}7$