Answer: 154.09 g
Step-by-step explanation:
3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe
The mass of MgCl2 produced is calculated:
m MgCl2 = 175 g FeCl3 * (1 mol FeCl3 / 162.2 g) * (3 mol MgCl2 / 2 mol FeCl3) * (95.21 g MgCl2 / 1 mol) = 154.09 g
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