Question

Solve the system of equatior x+2y=14 x-y=13​

Answer 1

x=40/3 2/3

Explanation:

Use elimination method for this. To do it, Multiply the x-y=13 by 2. It turns into 2x-2y=26. We have this

x+2y=14

2x-2y=26

Add because the signs are different for y each equation.

So 3x=40

x=40/3

14-40/3=2/3

y=2/3

x=40/3

Answer 2

y=7-x/2

y=-13+x

Explanation: