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Solve the system of equatior x+2y=14 x-y=13​
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5 votes
Solve the system of equatior x+2y=14 x-y=13​

User Kirstin
by
5.2k points

2 Answers

4 votes

Answer:

x=40/3 2/3

Explanation:

Use elimination method for this. To do it, Multiply the x-y=13 by 2. It turns into 2x-2y=26. We have this

x+2y=14

2x-2y=26

Add because the signs are different for y each equation.

So 3x=40

x=40/3

14-40/3=2/3

y=2/3

x=40/3

User Rombez
by
4.9k points
2 votes

Answer:

y=7-x/2

y=-13+x

Explanation:

User Barry Irvine
by
5.1k points
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