Question

Factor the expression completely 6x^2 + 21x - 12​

Answer 1

Answer:3(2−1)(+4)

Explanation:

62+2

1−1

6x^{2}+21x-12

6x2+21x−12

3(22+7x−4)

3(2x^{2}+7x-4)

3(2x2+7x−4)

3(22+7−4)

3(2x2+7x−4)

3(22+8−−4)

3(2x2+8x−x−4)

3(22+8−−4)

3(2x^{2}+8x-x-4)

3(2x2+8x−x−4)

3(2(+4)−1(+4))

3(2x(x+4)-1(x+4))

3(2x(x+4)−1(x+4))

3(2(+4)−1(+4))

3(2x(x+4)-1(x+4))

3(2x(x+4)−1(x+4))

3(2−1)(+4)