Explanation:
- JK = LM
- L is midpoint of JN ⇒ JL = LN = 1/2JN
- JK║LM and JN is a transversal ⇒
∠KJL and ∠MLN are corresponding angles ⇒
∠KJL ≅ ∠MLN
We have two sides and the included angle of ΔJLK congruent to two sides and the included angle of ΔLNM
Therefore ΔJLK ≅ ΔLNM by SAS rule