Question

A bag of marbles contains only the colors blue, yellow, and green.

If the probability of getting a yellow marble is 1/3, and the probability of getting a blue marble is 1/5, what is the probability of getting a green marble?

Answer 1

`(7)/(15)`

Explanation:

Given parameters:

Marbles in the bag = blue, yellow, and green

Pr(yellow) =
`(1)/(3)`

Pr(blue) =
`(1)/(5)`

Unknown:

Pr(green) = ?

Solution:

Probability is the likelihood of an event to occur;

For this problem;

Pr(yellow) + Pr(blue) + Pr(green) = 1

`(1)/(3)` +
`(1)/(5)` + Pr(green) = 1

Pr(green) = 1 - (
`(1)/(3)` +
`(1)/(5)` )

Pr(green) = 1 -
`(8)/(15)`

Pr(green) =
`(7)/(15)`