Question

Dry ice is carbon dioxide in the solid state. 1.28 grams of dry ice is placed in a 5.00 L chamber that is maintained at 35.1°C. What is the pressure in the chamber after all of the dry ice has sublimed? Assume ideal gas behavior.

Answer 1

0.15atm

Step-by-step explanation:

Given parameters:

Mass of dry ice = 1.28g

Volume of chamber = 5L

Temperature = 35.1°C = 35.1 + 273 = 308.1K

Unknown:

Pressure in the chamber = ?

Solution:

As we assume ideality for the gases in the cylinder, we use the equation below to solve the problem;

PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant = 0.082atmdm³mol⁻¹k⁻¹

T is the temperature

Let us find the number of moles;

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles of CO₂ =
`(mass)/(molar mass)`

Number of moles of CO₂ =
`(1.28)/(44)` = 0.03moles

So;

Input the parameters and solve;

P x 5 = 0.03 x 0.082 x 308.1

5P = 0.73

P =
`(0.73)/(5)` = 0.15atm