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How many grams are in 3 moles of KBr

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\text{Molar mass of KBr},~ M = 119.002~ \text{g mol}^(-1)


\text{No. of moles,}~ n = 3~ \text{mol.}\\\\\text{Mass of KBr},~ w = nM = 3 * 119.002= 357.006~ g\\\\\text{Hence, there are 357.006 grams in 3 moles of KBr.}

User Thomas Johan Eggum
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