Question

A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

Answer 1

The new volume : 0.07 L

Further explanation

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

`\rm p_1V_1=p_2.V_2\\\\(p_1)/(p_2)=(V_2)/(V_1)`

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

`\tt V_2=(P_1.V_1)/(P_2)\\\\V_2=(1* 0.39)/(5.6)\\\\v_2=\boxed{\bold{0.07~L}}`