Question

a stadium had 47,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C The number of seats in Section A equals the total number of seats in Section B and C. Suppose the stadium takes in $1,013,000 from each sold out event. How many seats does each section hold?

Answer 1

Section A has 15,666 seats, and sections B and C each have 31,334 seats.

Step-by-step explanation:

To solve this problem, let's denote the number of seats in section A as x. Since the number of seats in section A equals the total number of seats in Sections B and C, the total number of seats in sections B and C is also x. Therefore, the total number of seats in the stadium is x + x + x = 47,000. Simplifying this equation, we get 3x = 47,000, and dividing both sides by 3, we find that x = 15,666.67. Since the number of seats must be a whole number, we can round x down to 15,666.

Now that we know the number of seats in section A, we can easily find the number of seats in sections B and C by subtracting the number of seats in Section A from the total number of seats in the stadium. Therefore, there are 31,334 seats in both sections B and C.

To summarize:

• Section A: 15,666 seats
• Sections B and C: 31,334 seats each

Answer 2

Step-by-step explanation:

Section A holds 24,500 seats

Section B hold 14,400 seats

Section C holds 10,100 seats

Hope it help :)!