Question

Hi can someone pls answer my question. i srsly need it

*with complete solution pls :(​

Answer 1

• Focal length=f=10cm
• Object distance=u=-5cm
• Height of object=h=1.67cm
• Height of image=h'=?
• Image distance=v=?
• Magnification=m=?

Apply mirror formula

`\\ \tt\longmapsto (1)/(v)+(1)/(u)=(1)/(f)`

`\\ \tt\longmapsto (1)/(v)=(1)/(f)-(1)/(u)`

`\\ \tt\longmapsto (1)/(v)=(1)/(10)-(1)/(-5)`

`\\ \tt\longmapsto (1)/(v)=(1)/(10)+(1)/(5)`

`\\ \tt\longmapsto (1)/(v)=(1+2)/(10)`

`\\ \tt\longmapsto (1)/(v)=(3)/(10)`

`\\ \tt\longmapsto v=(10)/(3)`

`\\ \bf\longmapsto v=3.3cm`

Now

`\\ \tt\longmapsto m=(-v)/(u)=(-3.3)/(-5)=(3.3)/(5)=0.6`

Now

`\\ \tt\longmapsto m=(h')/(h)`

`\\ \tt\longmapsto h'=mh`

`\\ \tt\longmapsto h'=0.6(3.3)`

`\\ \tt\longmapsto h'=1.98cm`