Answer:
C log(1/5)
Explanation:
log 3-log 15 = -log _10^(5)
log 5 = log _10^(5)
log (-12) = log _10^(-12)
log (1/5) = -log _10^(5)
log 12 = log _10^(12)
Formula =======================
consider a and b two real numbers
where a > 0 and b > 0.
……………………………………………………………
log 3 − log 15
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