Answer:
Start by getting everything on the same side of the equals sign and then set it equal to 0. . Factor out the common tan^2x like this: . Now we have 2 separate equations to solve: and sinx = 0. Now we have to figure out where tan^2 is 0 between 0 and 2pi. If we include 2pi, the solutions for that equation are . You can test those out on your calculator just to be sure. There's only one value of x for the next equation. The only place between 0 and 2pi where the sin x = 1 is at x = . And there you go!
Explanation: