Question

A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force of 23 N?

Answer 1

The linear velocity of the object is 8.71 m/s.

Step-by-step explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

`F_c = (mv^2)/(r)\\\\`

where;

v is the linear velocity of the object

`F_c = (mv^2)/(r)\\\\mv^2 = F_cr\\\\v^2 = (F_cr)/(m)\\\\v= \sqrt{(F_cr)/(m)} \\\\v= \sqrt{(23*3.3)/(1)}\\\\v = 8.71 \ m/s`

Therefore, the linear velocity of the object is 8.71 m/s.