Question

Jessica has 3 cards in a bag,each marked with a letter. The letters are X, Y, and Z. Without looking, she reaches into the

bag, pulls out a
card, and then puts the card back in the bag. If Jessica does this 3 times, what is the probability she pulls out the X card first, then the Y
card, and then the Z card? In a fraction

Answer 1

The probability of pulling out the X card first, then the Y card, and then the Z card is 1/27.

Step-by-step explanation:

To find the probability that Jessica pulls out the X card first, then the Y card, and then the Z card, we multiply the probabilities of each event together.

Since Jessica puts the card back in the bag after each draw, the probability of pulling out the X card on the first draw is 1/3.

Similarly, the probability of pulling out the Y card on the second draw is also 1/3.

Finally, the probability of pulling out the Z card on the third draw is also 1/3.

Therefore, the overall probability is (1/3) * (1/3) * (1/3) = 1/27.