Answer:
The final speed of the electron is 6,497 km/s
Step-by-step explanation:
Given;
mass of the electron, m = 9.11 x 10⁻³¹ kg
electron potential, V = -120 V
Apply work energy theorem;
¹/₂mv² = eV
Where;
v is the final speed of the electron
e is the charge of the electron, = 1.602 x 10⁻¹⁹ C
![v = \sqrt{(2eV)/(m) }\\\\v = \sqrt{(2(1.602*10^(-19))(120))/(9.11*10^(-31)) }\\\\v = 6496473.75 \ m/s\\\\v = 6,497 \ km/s](https://img.qammunity.org/2021/formulas/physics/college/3cecnticqkllvrfzv2cqikpikw62e87gck.png)
Therefore, the final speed of the electron is 6,497 km/s